544=14x+x^2

Solution for 544=14x+x^2 equation:

544=14x+x^2

We move all terms to the left:

544-(14x+x^2)=0

We get rid of parentheses

-x^2-14x+544=0

We add all the numbers together, and all the variables

-1x^2-14x+544=0

a = -1; b = -14; c = +544;
Δ = b2-4ac
Δ = -142-4·(-1)·544
Δ = 2372
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2372}=\sqrt{4*593}=\sqrt{4}*\sqrt{593}=2\sqrt{593}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-2\sqrt{593}}{2*-1}=\frac{14-2\sqrt{593}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+2\sqrt{593}}{2*-1}=\frac{14+2\sqrt{593}}{-2}
$